Question

if sum of the reciprocal of 2 numbers is 6/35 and one number is 4 more than the other number then what is the number

Answer 1

The two numbers are x and x+4

(1/x)+(1/x+4)=6/35

(X+4+x)/x^2+4x=6/35

(2x+4)/x^2+4x=6/35

(2x+4)35=(x^2+4x)6

(X+2)35=(x^2+4x)3

35x+70=3x^2+12x

3x^2- 23x-70=0

3x^2-30x+7x-70=0

3x(x-10)+7(x-10)=0

(3x+7) (x-10)

X=10 and x= -7/3

We will choose the finite value x=10

10 and 14