If sum of the roots of the quadratic equation kx2+12x+8k=0 is equal to the product of its roots, then find the value of k.
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The sum and the product of the roots of the quadratic equation kx² + 12x + 8k = 0 are equal.
When we compare kx² + 12x + 8k = 0 to ax² + bx + c = 0, we get :
- a = k
- b = 12
- c = 8k
Given that :
- αβ = α + β . . . . . (1)
We know that :
- Product of zeroes (αβ) = c / a
⟹ 8k / k
⟹ 8
- Sum of zeroes (α+β) = - b / a
⟹ - 12 / k
Equating both from (1) :
⟹ 8 = - 12 / k
⟹ 8k = - 12
⟹ k = - 12 / 8
⟹ k = - 3 / 2
➤ Therefore, the value of k in kx² + 12x + 8k = 0 when the sum and product of the roots is equal is - 3 / 2.
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