If sum of the squares of zeroes of the quadratic polynomial x^2 -8x +k is 40,find the value of k
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given,
sum of the squares of zeroes of the quadratic polynomial x^2 -8x +k is 40
let roots of the equation be a,b
so,
a^2+b^2=40
sum of roots according to equation is 8
a+b=8
squaring on both sides we get,
a^2+b^2+2ab=64
40+2ab=64
2ab=24
ab=12
so product of roots is 12
and according to equation product of roots is k
so k=12
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