Question

If sum of the squares of zeros of the quadratic polynomial fx )= x2 8x k is 40 find the value of k

Answer 1

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Answer 2

On solving this Quadratic polynomial $f(x) = x^{2} -8x+k$

We get the answer $k = 12$

Step- by-step explanation:

Let a ,b be the zeroes of the polynomial. Then,

$a+b=8 and ab=k\\Given,\\a^{2}+b^{2} =40\\(a+b)^{2} -2ab=40\\64-2k=40\\2k=24\\k=12$

so, the value of k = 12

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