if sum of the squares of zeros of the quadratic polynomial f(y)=y^2-8y+p is 40 , find the value of p
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the Value of p is 12
the Value of p is 12
P(x)=x^2-8x+p
P(x)=Ax^2+BX+C(the equation is formed)
Let the zeroes be'a' and'b'
It is given that
=a^2+b^2=40
=(a+b)^2-2ab=40___1
Sum of zeroes
=a+b=-B/A=-(-8)/1=8
Product of zeroes
=a×b=c/a=p
Substitute these value in equation 1 we get
=8^2-2p=40
=64-2p=40
=2p=24
=p=12x
the Value of p is 12
P(x)=x^2-8x+p
P(x)=Ax^2+BX+C(the equation is formed)
Let the zeroes be'a' and'b'
It is given that
=a^2+b^2=40
=(a+b)^2-2ab=40___1
Sum of zeroes
=a+b=-B/A=-(-8)/1=8
Product of zeroes
=a×b=c/a=p
Substitute these value in equation 1 we get
=8^2-2p=40
=64-2p=40
=2p=24
=p=12x
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the Value of p is 12
P(x)=x^2-8x+p
P(x)=Ax^2+BX+C(the equation is formed)
Let the zeroes be'a' and'b'
It is given that
=a^2+b^2=40
=(a+b)^2-2ab=40___1
Sum of zeroes
=a+b=-B/A=-(-8)/1=8
Product of zeroes
=a×b=c/a=p
Substitute these value in equation 1 we get
=8^2-2p=40
=64-2p=40
=2p=24
=p=12x
P(x)=x^2-8x+p
P(x)=Ax^2+BX+C(the equation is formed)
Let the zeroes be'a' and'b'
It is given that
=a^2+b^2=40
=(a+b)^2-2ab=40___1
Sum of zeroes
=a+b=-B/A=-(-8)/1=8
Product of zeroes
=a×b=c/a=p
Substitute these value in equation 1 we get
=8^2-2p=40
=64-2p=40
=2p=24
=p=12x
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