if sum of the squares of zeros of the quartic polynomial f(x)=x^2-8x+k is 40 . find the value of k
Answers
Answered by
1
Sum of squares of zeroes = alpha² + beta² = (alpha + beta)² - 2 alpha beta
40 = (-b/a)² - c/a
= b²/a² - c/a
= 64/1 - k
40 = 64 - k
k = - 24
40 = (-b/a)² - c/a
= b²/a² - c/a
= 64/1 - k
40 = 64 - k
k = - 24
saketpc:
Oh sorry!! wait
Its -12
Instead of K write 2k thats all
thanx Bro
but bhai answer -12 nhi +12 a raha hai
ok ok I got it minus on RHS and minus on LHS be get cut
Wapas galti!!
12 Hi aayega
Not -12
yo
Similar questions