if sum of the three numbers of AP is 36 ,find the middle term.
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the middle term is 12.
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hope it helps you.
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Let Terms of AP be a-d,a and a+d
We are given, a -d + a + a + d = 36
3a = 36
so, a = 12
But S3 = 36
so, 3/2[2a + 11d] = 36
3[2a + 11d] = 72
so, 2a + 11d = 24
By putting a = 12
2(12) + 11d = 24
so, 11d = 24 - 24
so, d = 0
Hence, middle term = a = 12
We are given, a -d + a + a + d = 36
3a = 36
so, a = 12
But S3 = 36
so, 3/2[2a + 11d] = 36
3[2a + 11d] = 72
so, 2a + 11d = 24
By putting a = 12
2(12) + 11d = 24
so, 11d = 24 - 24
so, d = 0
Hence, middle term = a = 12
Aathi11:
thank-you
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