Question

if sum of the zeroes is 9 and product of the zeroes is 14 then find the quadratic polynomial.​

Answer 1

Given,

☛ sum of zeroes = 9

☛ product of zeroes = 14

To Find,

- Quadratic polynomial

Solution

We know,

☛ p(x) = x² - ( sum of zeroes )x + (product of zeroes)

☛ p(x) = x² - 9x + 14

Answer 2

Answer:

$let \: \alpha \: and \: \beta \: be \: the \: zeroes \: of \: the \: polynomial$

$then \: ( \alpha + \beta ) = 9 \: and \: ( \alpha \beta ) = 14$

So,the required polynomial is -

$x^2 - ( \alpha + \beta )x + ( \alpha \beta )$

$x^2 -9x +14$

Hope it's helpful to u

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