Question

if sum of the zeroes of 7x^2-px+1 is 9 then find p

Answer 1

p(x) = 7x^2-px=1

let the zeroes be A&B

=> A+B = 9 = -b/a  [b= -p, a=7]

=> 9 = -(-p)/7

=> 9= p/7

=> 9*7= p

=> 63 = p

Answer 2

p(x) = 7x^2-px=1

let the zeroes be A&B

=> A+B = 9 = -b/a  [b= -p, a=7]

=> 9 = -(-p)/7

=> 9= p/7

=> 9*7= p

=> 63 = p

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