If sum of the zeroes of a quadratic polynominal f(t) =kt2+2t+3k is equal to their product find the value of k
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Hiii friend,
Let Alpha and beta are the two zeroes of the GIVEN POLYNOMIAL.
P(T) = KT²+2T+3K
Here,
A = K , B = 2 and C = 3K
Therefore,
Sum of zeroes = -B/A
Alpha + Beta = -2/K
And,
Product of zeroes = C/A
Alpha × Beta = 3K/K = 3
According to question,
Sum of zeroes = Product of zeroes
Alpha + Beta = Alpha × Beta
-2/K = 3
3k = -2
K = -2/3.
HOPE IT WILL HELP YOU........ :-)
Let Alpha and beta are the two zeroes of the GIVEN POLYNOMIAL.
P(T) = KT²+2T+3K
Here,
A = K , B = 2 and C = 3K
Therefore,
Sum of zeroes = -B/A
Alpha + Beta = -2/K
And,
Product of zeroes = C/A
Alpha × Beta = 3K/K = 3
According to question,
Sum of zeroes = Product of zeroes
Alpha + Beta = Alpha × Beta
-2/K = 3
3k = -2
K = -2/3.
HOPE IT WILL HELP YOU........ :-)
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