Question

If sum of the Zeroes of the polynomial P(x)= (k²-14)x²-2x-12 is 1 , then the value(s) of 'k' is/are​

Answer 1

(kx)^2 - 14x^2 - 2x -12

k^2-14-2-12=0

k^2-28=0

k^2=28

k=

$\sqrt{28}$