Question

if sum of the zeroes of the quadratic polynomial 3x²- kx+6 is 3 then find the value of k​

Answer 1

Answer:

Hi ,

Compare 3x² - kx + 6

with ax² + bx + c,

a = 3 ,

b = - k ,

c = 6 ,

According to the problem given ,

Sum of the zeroes = 3 ---( 1 )

- b / a = 3

- ( - k ) / 3 = 3

k / 3 = 3

k = 9

I hope this helps you.

:

Answer 2

Answer:

Step-by-step explanation:

3x²- kx+ 6  = 0

sum of zeroes = 3

α + β = 3

-b/a = 3

- (-k) /3 = 3

k/3 = 3

k = 9