If sum of the zeros of a quadratic polynomial 3x^2-kx+6 is 3,then find the value of k
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For this k value must be 9
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Answer:
polynomial is 3x^2 - kx + 6
here a=3 , b=-k , c=6
sum of the zeroes , -b/a=3 [ given ]
-(-k)/3=3
k=9
Step-by-step explanation:
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