If sum of the zeros of the q p in f(x) =px^2+2x+3p is equal to their product, the value of product is
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Answered by
3
hey mate
here is your answer
sum of the zeros = product of the zeros
-b/a=c/a
-b=c
-2=3p
p=-2/3
the value of the product=c/a
=3p/p
=3(answer)
here is your answer
sum of the zeros = product of the zeros
-b/a=c/a
-b=c
-2=3p
p=-2/3
the value of the product=c/a
=3p/p
=3(answer)
Answered by
0
Sum of the Zeros= Product of the zeros
⇒ -b/a=c/a
⇒ -b=c
⇒ -2=3p
⇒ p= -2/3
The value of the product=c/a
=3p/p
=3
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