Question

if sum of three consutive number is 66. find the number​

Answer 1

Answer:

Let, the three numbers be 'x' 'x+1' and 'x+2'

B/Q

x+x+1+x+2= 66

3x+3=66

3x=66-3

3x = 63

x=63/3

x=21

Therefore the numbers are 21 , 22 and 23

Answer 2

Answer:-

$\pink{\bigstar}$ The numbers are

$\large\leadsto\boxed{\tt\purple{21}}$

$\large\leadsto\boxed{\tt\purple{22}}$

$\large\leadsto\boxed{\tt\purple{23}}$

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• Given:-

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• Sum of three consecutive numbers is 66.

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• To Find:-

• The numbers = ?

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• Solution:-

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Let the three consecutive numbers be 'x' , 'x+1' and 'x+2' respectively.

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• According to the question:-

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➪ $\sf x + (x + 1) + (x + 2) = 66$

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➪ $\sf x + x + 1 + x + 2 = 66$

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➪ $\sf 3x + 3 = 66$

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➪ $\sf 3x = 66 - 3$

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➪ $\sf 3x = 63$

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➪ $\sf x = \dfrac{63}{3}$

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★ $\large{\bf\red{x = 21}}$

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Hence, the numbers are

• x = 21

• x + 1 = 21 + 1 = 22

• x+2 = 21 + 2 = 23

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Therefore, the three consecutive numbers are 21, 22 and 23 respectively.