Question

If sum of three numbers in A.P is 33 and sum of their squares id 491, then what are 1
three numbers.
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Answer 1

let the numbers be a-d, a and a+d

then, their sum i.e. 3a=33

a=11

and sum of their squares,

(a-d)²+a²+(a+d)²=491

(11-d)²+121+(11+d)²=491

(11-d)²+(11+d)²=370

121+d²-22d + 121+d²+22d =370

2d²= I28

d²=64

d=8

hence, the numbers are 3,11 and 19

Answer 2

i hope this will help you.