If sum of two numbers is 10.Find the maximum value of the sum of their reciprocals?
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Answer:
sum of two no.=10
sum of their reciprocal=5/12
CALCULATION:
let the no. be x and y
so,x+y=10 ...(i)
and,(1/x)+(1/y)=5/12 ....(ii)
= (x+y)/xy=5/12
now,
=10/xy=5/12
xy=12×2=24....(iii)
Now,(10-y)× y=24
=10y-y²=24
=y²-10y+24=0
=y²-6y-4y+24=0
=y(y-6)-4(y-6)=0
=(y-6)(y-4)=0
=y=6,4
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