if sum of two numbers is 30 and their difference is 8, what their product is?
Answers
Answered by
19
let the no. be (x) and (8+x)
when,
x+8+x=30
2x+ 8=30
2x=30-8
x=22/2
x=11
8+x=11+8=19
then their product will be ,
19×11=209
when,
x+8+x=30
2x+ 8=30
2x=30-8
x=22/2
x=11
8+x=11+8=19
then their product will be ,
19×11=209
Answered by
51
Answer:
Numbers are 19 and 11.
Product is 209.
Step-by-step explanation:
Let the two numbers be x and y respectively.
According to the question ;
x + y = 30 ....(i)
x - y = 8 .... (ii)
Adding equation (i) and (ii),
⇒ x + y + x - y = 30 + 8
⇒ 2x = 38
⇒ x =
⇒ x = 19
Now, substituting the value of x in equation (i), we get ;
x + y = 6
⇒ 19 + y = 30
⇒ y = 30 - 19
⇒ y = 11
Hence, the required numbers are 19 and 11 respectively.
Their product = 19 * 11 = 209
Therefore, the answer is 209.
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