If sum of two numbers is128 and difference between them is 32 then find the numbers
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1
Answer:
80 & 48
Step-by-step explanation:
x+y=128
x-y=32
then solve it you will get the value
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Answered by
1
Step-by-step explanation:
let the numbers a and b
a+b=128
a-b=32
therefore we have to Equate both
a+b+a-b=128+32
2a= 160
a= 160/2=80
finding b by putting value of a in first equation
80+b=128
b=128-80
b=48
therefore the numbers are 80 and 48
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