Question

If sum of zeroes of *p(x) = 6x² - 13x + (3m-9)* are reciprocal of each other *find m*...?​

Answer 1

Answer:

if (x-z). (x-1/z) is zeroes

x= z. x=1/z

6(z)² - 13z + (3m-9)=6(1/z)² - 13(1/z) + (3m-9)

6z² - 13z + (3m-9)=6/z² - 13/z + (3m-9)

6z² - 13z=6/z² - 13/z

(6z - 13)z=(6-13z)/z²

(6z - 13)=(6-13z)/z

6z - 13=6z-13z²

- 13= - 13z²

1 = z²

=> z = 1

(x-1). (x-1/1)

x=1. x=1

p(1)=6(1)² - 13*1 + (3m-9)=0

6 - 13 + (3m-9)=0

3m-9 = -7

3m = -7+9

m = 2/3