Question

If sum of zeroes of p(x)=(k²-14)x²-2x-4 is 1 then find value of k

Answer 1

$p(1) = (k {}^{2} - 14)1 {}^{2} - 2(1) - 4 \\k {}^{2} - 16 - 4 \\ 0 = k {}^{2} - 20 \\ 20 = k { }^{2} \\ \sqrt{20 } = k \ \:$
so root 20 is the answer