Question

If sum of zeroes of the polynomial f(x)= 2 x³ -3 k x²+4 x-5 is 6 then value of k is

Answer 1

Answer:

$f(x) = 2 {x}^{3} - 3k {x}^{2} + 4x - 5 \\ given \: sum \: of \: zeroes \: of \: f(x) \: is \: 6 \\ = > \frac{ - 3k}{2} = 6 \\ = > - 3k = 12 \\ = > k = \frac{12}{ - 3} \\ hence \: k = - 4$