If sum of zeroes of the quadratic polynomial 2x² + kx-6 is 2, then value of k is:
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In a general quadratic equation of form ax2+bx+c=0, sum of roots are by a−b.
In the given quadratic equation, 3x2−kx+6=0
a=3,b=−k,c=6
Sum of roots =a−b=3−(−k)=3k
and sum of roots is given 3
⇒3k=3
⇒k=9
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Compare 2x² + kx - 6 with ax² + bx + c,
a = 2 ,
b = k ,
c = -6 ,
According to the problem given ,
Sum of the zeroes = 2
- b / a = 2
- k / 2 = 2
k = -4
Explanation:
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