Question

if sum of zeroes of the quadratic polynomial ky square + 2y-3k is equal to twice their product of zeros find the value of k​

Answer 1

Answer:

Quadratic equation is

Ky² + 2y - 3k

Let α and β are its two zeros

The sum of zeros = α + β = -b/a

product of zeros = αβ =ab

Given condition. α + β = 2× αβ

-2 / k = -2×3k/k

-6k = -2

k =2/6

k = 1/3

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