Question

if sum of zeros of the polynomial p(y)=ky2+2y+3k is equal to their product find value of k

Answer 1

p(y)=ky^2+2y+3k
now,
sum of the roots=product of the roots
-2/k = 3k/k
-2/k = 3
-2 = 3k
k = -2/3

hope this helps:p

Answer 2

Given
ky² + 2y + 3k

Here, a = k , b = 2 , c = 3k

Now the sum of the zeroes = -b/a = -2/k
Product of zeroes = c/a = 3k/k = 3

Now A/Q --
 -2/k = 3
k = -2/3

Value of k = -2/3

Hope This Helps You!