If sume of 1st term is 513 and terms are 54,51,48 then find the n.term
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hey mate
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here is ur answer
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sn = n/2 {2a+(n-1)d}
sn = 513
a=54
d=3
513= n/2{2×54+(n-1)3}
513=n/2{108+(n-1)3}
513×2= 108n+3n-3n
1026=108n+3n²-3n
⬇⬇⬇⬇⬇
here is ur answer
⬇⬇⬇⬇⬇
sn = n/2 {2a+(n-1)d}
sn = 513
a=54
d=3
513= n/2{2×54+(n-1)3}
513=n/2{108+(n-1)3}
513×2= 108n+3n-3n
1026=108n+3n²-3n
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