Question

If sun's elevation is 60 then a pole of height 6m will cast a shadow of length?

Answer 1

$\tan(\theta) = \dfrac{\text{opp}}{\text{adj}}$

$\tan(60 \textdegree) = \dfrac{\text{6}}{\text{shadow}}$

$\text{shadow} = \dfrac{\text{6}}{\tan( 60\textdegree)}$

$\text{shadow} = 3.46 \text{ m}$

Answer: The length of the shadow will be 3.46m

Answer 2

tan(60°) = 6/shadow

shadow= 6/tan(60)°

Shadow= 3.46m