Question

If sun's elevation is 60° then a pole of height 6m will cast a shadow of length

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$\red {Length \:of \:the \:shadow (BC)}\green {=2\sqrt{3}\:cm }$

Step-by-step explanation:

$Height \:of \:the \: pole (AB) = 6\:cm$

$Angle \:of \: elevation \:\angle ACB = 60\degree$

$Length \:of \:the \:shadow (BC) =?$

$tan \:60\degree = \frac{AB}{CB}$

$\implies \sqrt{3} = \frac{6}{CB}$

$\implies BC = \frac{6}{\sqrt{3}}\\=\frac{6\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}\\=\frac{6\times \sqrt{3}}{3}\\=2\sqrt{3}$

Therefore.,

$\red {Length \:of \:the \:shadow (BC)}\green {=2\sqrt{3}\:cm }$

•••♪