Question

If surface tension of water is 0.07N/m the weight of water supported in capillary tube of radius 0.1mm is​

Answer 1

Answer:

S=7×10

−2

N/m,

r=0.1mm=0.1×10

−3

m

F=mg

⇒Sl=mg

⇒mg=S×2πr

∴ Weight of water

=7×10

−2

×2×

7

22

×0.1×10

−3

=44×10

−6

N

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