Question

. If Sushant rides his bicycle at the speed of 2 km/hr, he reaches his school late by 1 minute. On increasing the
speed by 2 km/hr, he reaches 5 minutes early. Find the distance between his school and his house(correct answer is 6km)​

Answer 1

Answer:

at speed of 2km/hr ,he is late by 1 minute

after increasing his speed by 2km/hr , his speed is 4km/hr (2+2) he is earlier by 5 minute

distance = (product of two speed/ difference of two speed )* difference in time arrival

distance= (2 * 4 / 2) *( 6 / 60)

distance = 4/10 or 400m.

second way

Using distance = speed * time

d = 2 ( T +1/60) since he is late by 1/60 hour .

d = 4( T -5/60) since he is earlier by 5/60 hour.

2 ( T +1/60) = 4( T -5/60)

T = 11/60 hour

d = 2( 12/60) = 24/60 km = 0.4 km = 400 m