Question

if Sushant rides his bicycle at the speed of 2 km per hour he reaches School late by 1 minute on increasing the speed by 2 kilometre per hour he reaches 5 min early find the distance between His
school and his house

Answer 1

If d is the required distance and T is the correct time,

Using distance = speed * time

d = 2 ( T +1/60) since he is late by 1/60 hour .

d = 4( T -5/60) since he is earlier by 5/60 hour.

2 ( T +1/60) = 4( T -5/60)

T = 11/60 hour

d = 2( 12/60) = 24/60 km = 0.4 km = 400 m

Answer 2

If d is the required distance and T is the correct time,

Using distance = speed * time

d = 2 ( T +1/60) since he is late by 1/60 hour .

d = 4( T -5/60) since he is earlier by 5/60 hour.

2 ( T +1/60) = 4( T -5/60)

T = 11/60 hour

d = 2( 12/60) = 24/60 km = 0.4 km = 400 m

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