Question

if t = (2,3,5,7,9,11,13 and M= (2,4,7,8,9,11 ) then find T U m and T N m

Answer 1

Answer:

Correct option is

A

m+n−p

Let 'a' be the first term and 'd' be common difference of the A.P

⇒T

m

=a+(m−1)d=n⇒a−d=n−md...(1)

and T

n

=a+(n−1)d=m⇒a−d=m−nd..(2)

Using (1) and (2) we get, d=−1 and a=n+m−1

∴T

p

=a+(p−1)=n+m−1+(p−1)(−1)=n+m−p

Hence, option 'A' is correct.