Question

If t^n=2^n+n then S5=?

Answer 1

Answer:

77.

Step-by-step explanation

Here,   tn is given.

So,  S5=t1+t2+t3+t4+t5

and  t1=$2^{1} +1$=3.

       t2=$2^{2}+2$=6.

       t3=$2^{3}+3$=11.

       t4=$2^{4}+4$=20.

       t5=$2^{5}+5$=37.

Therefore,S5=3+6+11+20+37=77.