If
T
W
O
^2 = THREE where the alphabets are single-digit integers then find T + W + O
Answers
Given : TWO² = THREE where the alphabets are single-digit integers
To Find : T + W + O
a)12
b)25
c)18
d)29
Solution:
TWO² = THREE
alphabets are single-digit integers
TWO is three digit numbers
and THREE is 5 digit numbers
Hence T must be 1
T = 1
Now trying different possible combination
TWO are different digits
Hence can be 102 , 103 , 104 , 105 , 106 , 107 , 108 , 109 , 120 , 123 , 124 , 125 , 126 , 127 , 128 , 129 , 130 , 132 , 134 , 135 , 136 , 137 , 138 , 139 , 140
142² is 6 digit number
number ending with 0 are not possible as then O = 0 and E = 0
Hence only 138² = 19044 end with repeated digit
T = 1 W = 3 , O = 8
H = 9 , R = 0 , E = 4
T + W + O = 1 + 3 + 8 = 12
T + W + O = 12
Simple method :
based on given options :
TWO is three digit numbers
and THREE is 5 digit numbers
Hence T must be 1
T = 1
now 1 + 9 + 8 = 18 is maximum possible value
so 25 and 29 are not possible
but 189² or 198² is 6 digit number hence not possible
so only possible solution in given option is 12.
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