If t = x + x ^2 then find velocity
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Acceleration and displacement are related as a = x²
we know, acceleration , a =
so, x² =
⇒x²dx = vdv
⇒∫x²dx = ∫vdv
at x = 0 , body is in rest ∴ initial velocity , v₀ = 0
Let velocity at x = 2 is v
Now,
⇒ [x³/3]²₀ =
⇒8/3 = v²/2
⇒16/3 = v²
So, v = ±4/√3 m/s
Hence, magnitude of velocity = 4/√3 m/s
saiprasad8389brainly:
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v=ds/dt
On differentiating,
Answer : v=1+x
Have doubt then you can comment
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