Question

if t=y+2t^2 find dy/dt​

Answer 1

Answer:

Heya user......❤

Given,

y = t + 2 t^2

Hence,

dy / dt

= d/dt ( t +2 t^2)

=1 + 2 ×2 t

= 1 + 4t

Hope it’s helpful...... ☺

Answer 2

Answer:

dydx=2(t2+t+1)

Explanation:

For parametric form of equation, dydx=dydtdxdt.

Here as x=t2−2t, dxdt=2t−2=2(t−1)

and as y=t4−4t, dydt=4t3−4=4(t3−1)=4(t−1)(t2+t+1)

Hence dydx=4(t−1)(t2+t+1)2(t−1)=2(t2+t+1)