if t1=5, t11=55 then find sum of first 11 terms.
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heya your answer.................................
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roh4:
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here is ur ans
a=5
a+10d=55
5+10d=55
10d=50
d=5
Sn=n/2(2a+(n-1)d)
sn=11/2(10+10*5)
=11/2(60)
=11*30
=330
hope it helps
mark BRAINLIEST
a=5
a+10d=55
5+10d=55
10d=50
d=5
Sn=n/2(2a+(n-1)d)
sn=11/2(10+10*5)
=11/2(60)
=11*30
=330
hope it helps
mark BRAINLIEST
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