If t10 = 27 and t17 = 48 then find the value of tn
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Answer:
a+(17-1)d =48
a+(10-1)d = 27
a+16d = 48
a+9d = 27
7d = 21
d = 3
a+16(3)=48
a+48=48
a = 0
tn = a+(n-1)d
tn= 0+(n-1)(3)
tn = 3n-3
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