If t11 =16 t21=29 find a+d
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Step-by-step explanation:
t11 = 16 and t21 = 29 [Given]
We know that,
tn = a + (n – 1 )d
t11 = a + (11 – 1 )d
∴ 16 = a + 10d ---------eq. no. 1
t21 = a + (21 – 1) d
∴ 29 = a + 20 d --------eq. no. 2
Subtracting eq. 1 from eq. 2
29 = a + 20 d
16 = a + 10d
13 = 0 + 10d
13 = 10d
13/10 = d
∴ d = 1.3
Substituting d = 1.3 in eq. no. 1
16 = a + 10d
16 = a + 10(1.3)
16 = a + 13
16 – 13 = a
∴ a = 3
a + d = 3 + 1.3
∴ a + d = 4.3
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