If t5=20, S15=210, find d and t15.
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t(15) - t(11) = 12
a + 14d - [ a + 10d] = 12
a + 14d - a - 10d = 12
14d - 10d = 12
4d = 12
d = 12/4
d = 3
Common difference = 3
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