Question

If t54 of an A:P. is - 61 and t4 = 64,
find t10
Salact​

Answer 1

Step-by-step explanation:

Let a be the first term and d be the common difference

so t

54

=a+53d=−61 (i)

and t

4

=a+3d=64 (ii)

equation (i)-(ii) we get

⇒ 50d=−125

d=−

2

5

⇒ a=

2

143

so t

10

=

2

143

+9(−

2

5

)=49

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Answer 2

Answer:

tn = a+ (n-1) d

t54 = a + 53d = - 61

similarly

+4 = a+ 3d =64

a+ 53d=-61

a+ 3d = 64

from subraction

50 d = - 125

d= 5divided 2

a= 143 divided by 2

t 10 = a + 9 d

= 143 ÷ 2) + 9 ( -5 ÷ 2)

Step-by-step explanation:

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