Question

If tan 0 = 1, then the value of
8 sin A+5 cose
sin - 2 cos + 7 cos e
is​

Answer 1

Answer:

tanθ=2

Now, sin2θ+2cos2θ+3cosθ8sinθ+5cosθ

= cos3θ×(tan3θ+2+cos2θ3)cosθ(8tanθ+5)

= tan3θ+2+3sec2θsec2θ(8tanθ+5)=tan3θ+2+3(1+tan2θ)(1+tan2θ)(8tanθ+5)

= 23+2+3(1+22)(1+22)(8×2+5)=10+155×21=25