If tan 0 = 12/5 and cos 0 = -5/13, then what is sin 0
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Answered by
1
Answer:
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Step-by-step explanation:
tan θ = sinθ/cosθ
12/5 = sinθ/(-5)/13
12/5 × (-5)/13 = sinθ
Therefore, sinθ = -12/13
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Answered by
2
Answer:
tanA=12/5
cos A =-5/13
tan= p/b
cos=b/h
sin = p/h
sin = 12/13
SREXPERIMENTKING4:
hi
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