Question

If tan 0 = 3, then (4sino-coso)/(4sino+coso) is equal to (a) 2/3 (b) 1/3 (c) 1/2 (d) 3/4
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Answer 1

Answer:

take 0=x

thanx=tan0

tanx=3

sinx/cosx=3

sinx=3cosx

sinx=3/2√2

cosx=1/2√2

4sinx-cosx/4sinx+cosx=

{4(3/2√2)-1/2√2}/{4(3/2√2+1/2√2)}=

(12/2√2-1/2√2)/(12/2√2+1/2√2)=

(11/2√2)/(13/2√2)=

11/13