Question

If tan 0 =7/8
then the value of
(1+sin)(1-sin)
(1+cos 0) (1 -cos)
8​

Answer 1

Answer:

If,

tanx = 7/8,

Then,

sinx = 7/√113

cosx = 8/√113

Solution:

(1-sin²x)(1-cos²x)

= (cos²x)(sin²x)

= (7².8²)/113

= 3136/113

Answer 2

Answer:

hey mate !

Step-by-step explanation:

if tan theta =7/8 (p/b)

then hypotenuse : √ 7^2+8^2

= √49+64

= √113

Now,

(1+sin theta) (1- sin theta)(1+cos theta)(1-cos theta)8

= (1- sin ^2 theta)(1- cos^2 theta ) 8

= (cos^2 theta)(sin^2 theta ) 8

= (8/√113)(7/√113) 8

= 56/113 * 8

= 0.495 * 8

= 3.96 answer.

4 approx

hope it helps !