If tan 0 + cot 0 = 2, prove that tan- 0 + cot? 0 = 2.
plz give me solution....
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tan0 + cot0 = 2.
=> (tan0 + cot0)² = (2)².
=> tan²0 + cot²0 + 2tan0.cot0 = 4.
=> tan²0 - cot²0 = 4tan0.cot0.
=> (tan0 - cot0)(tan0 + cot0) = 4tan0.cot0.
=> tan0 - cot0 = 4tan0.cot0/tan0 + cot0.
=> tan0 - cot0 = 4tan0.cot0/2.
- => tan0 - cot0 = 2 = RHS.
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