Question

) If tan 0 + cot 0 = 2, prove that tan³ 0 + cot³ 0 = 2.​

Answer 1

Step by step explanation:-

Given to prove :-

tanθ + cotθ = 2 and to prove tan³θ + cot³θ = 2

Solution :-

Lets prove !

tanθ + cotθ = 2

Cubing on both sides

(tanθ + cotθ)³ = (2)³

(a + b )³ = a³ + b³ + 3ab ( a + b )

tan³θ + cot³θ + 3tanθcotθ (tanθ + cotθ) = 8

We know tanθ × cotθ = 1

tan³θ + cot³θ +3(2) = 8

tan³θ + cot³θ + 6 = 8

tan³θ + cot³θ = 8-6

tan³θ + cot³θ = 2

Hence proved !

Know more :-

Trigonmetric Identities:-

sin²θ + cos²θ = 1

sec²θ - tan²θ = 1

csc²θ - cot²θ = 1

Trigonmetric relations

sinθ = 1/cscθ

cosθ = 1 /secθ

tanθ = 1/cotθ

tanθ = sinθ/cosθ

cotθ = cosθ/sinθ

Trigonmetric ratios

sinθ = opp/hyp

cosθ = adj/hyp

tanθ = opp/adj

cotθ = adj/opp

cscθ = hyp/opp

secθ = hyp/adj

Answer 2

Answer:

it is yes

Step-by-step explanation:

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