if tan=1/2& tabb=1/3 then A+B=
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0
Step-by-step explanation:
tan(A+B)=tanA+ tanB/1-tanA*tanB
tan(A+B)=1/2+1/3/1-1/6
=5/6/5/6
tan(A+B)=1
A+B=45°
Answered by
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1
Step-by-step explanation:
tan(A+B)= tanA+tanB/1-tanAtanB
=(1/2)+(1/3)/[1-1/2*1/3]
= [(3+2)/6]/[(6-1)/6]
= (5/6)/(5/6)
= 1
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