if tan=1/2 and tan(A+B)=7/9 find the value of B
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Answer:
tan(A+B)= (tanA+tanB)/(1-tanA*tanB)
Substitute given value of tan(A+B)=2
We get (tanA+tanB)/(1-tanA*tanB)=2
Also given tanB=1/2
Hence we get
(tanA+1/2)/(1-tanA*1/2) =2
Or (2tanA+1)/(2-tanA)=2
Or 2tanA+1=4–2tanA
Or 4tanA=3
Or tanA=3/4
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