If tanθ=1/√2, Find the value of (cosec^2θ-sec^2θ)/(cosec^2θ+cot^2θ)
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let tita be'a'
sin a/cos a=1/√2
1/coseca/1/seca=1/√2
seca/coseca=1/√2
=>seca=1
=>coseca=√2
=>cot a =1/tana=√2
[(√2)^2-(1)^2]/[(√2)^2+(√2)^2]
(2-1)/(2+2)
=1/4
sin a/cos a=1/√2
1/coseca/1/seca=1/√2
seca/coseca=1/√2
=>seca=1
=>coseca=√2
=>cot a =1/tana=√2
[(√2)^2-(1)^2]/[(√2)^2+(√2)^2]
(2-1)/(2+2)
=1/4
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